In the former Section, we have assumed that
and
were
precisely known. In practice, we have to guess them from what is really
known. The fact that these parameters are the ones usually used to
summarize the dispersion properties of a population doesn't prove
that these parameters are the optimal ones in the specific context
of optimizing the newsboy problem.
To introduce what other parameter could be used to evaluate this dispersion,
let us consider in detail what happens when the ordered quantity
is chosen exactly equal to the expected demand.
Knowing that
is not the optimal inventory, we can
nevertheless examine what happens when this choice is taken. By the
definition of the mean, we have
.
Substituting the variable
in eq:cost-of-uncertainty
by this expression of
, we obtain:
The quantity
(further referred as the intermeans parameter)
has some similarity with the interquartile range, where one subtracts
the median of the left hand part from the median of the right hand
part, both parts being separated by the median of the population.
Here we use the means and subtract the mean of the left part from
the mean of the right part, both parts being separated by the mean
of the population, the result being afterwards multiplied by
.
Therefore
appears to be a measure of the dispersion of the
distribution.
Since this use of
seems to be new, we have undertaken a comparison
between this quantity and the usual measure of the dispersion, i.e.
the standard deviation
. This leads to tab:comparison-delta-sigma,
where it could be noticed that the ratio
is quite
the same for all triangular distributions, whatever their skewness.
|
For the lognormal distribution, the ratio
varies.
For the wildest ones, i.e. for
, one has
. But, in the not so wild case, i.e. when
the demand has only one chance over thousand to go outside the interval
, the relation
holds. Moreover, it can be noticed that
so that:
From eq:cost-of-mean and tab:comparison-delta-sigma
we have the following result: if the demand is assumed to be either
normal or lognormal, the cost of uncertainties is bounded by:
Many alternative proofs of the "Scarf's rule" have
been given ([Gallego 1993,Yue 2006]). What follows concerns the second
part of the original proof. Apart its relevance to the Scarf's theorem,
this proof will indicate how to find the best decision against the
family.
The proof given by H. Scarf for the bound eq:scarf-bound
was divided in two steps, the first one being to prove that, over
all the distributions
, the worst
case for a given
is obtained by an ad hoc "two
Dirac's" distribution. Therefore finding the best order against
is reduced into finding the best order
against
.
The second step can be done as summarized by fig:maxminscarf
(where
,
,
and
, inducing
). All the curves
corresponding to the different values of the ordered quantity
are going through the same point, whose abscissa is
.
More precisely, all these curves are made of rectilinear and "parabolic"
pieces and all the complete "parabolae" are going
through this same point. The conclusion is straightforward: the best
decision is the
whose curve admits this special point as its
minimum.
Having seen the fact of the confluence, a formal proof is easy to
obtain. The "parabolic" part of
can be rewritten as:
When using two Dirac's distributions, we have
so that
, the greatest value corresponding
to
, i.e. the symmetric case. Therefore, the assumptions
"knowing
" and "knowing
" are no more quite equivalent
as they were in tab:comparison-delta-sigma.
fig:maxmindou show what happens when drawing the curves
for different values of
the ordered quantity
. Now, the "parabolic"
parts are straight lines. But here again, all of them are going through
the same point whose abscissa is
This is comforted
by:
And therefore, the robust decision is no more given by eq:scarf-bound
but by: