Let us now prove:
As an illustration of this theorem, Fig. 4 (left) shows
the sequence of the lower bounds relative to
and
for an M/D/1 queue (i.e. for a deterministic service distribution) where
,
while Fig. 4 (right) shows some
values.
Inequality (6) may be proved in the same way as the left hand
inequality in (5). It leads to a global lower bound of the conditional
waiting time pdf. The only existence of a
satisfying inequality
(7) is trivial (
works !): what is to be proved
is that an optimal value can be derived and that the corresponding
is meaningful.
Let us begin by computing the coordinate
where the two curves
and
intersect. Figure
5 plots
and
against
: the resulting graph appears as almost rectilinear. Computing the regression
line (M/GI/1 file, with the given values of parameters) leads to
and
. Each of these regression lines
is "strongly explicative", since it reduces the standard deviation
of the
's by a factor 300.
Observing that
induces
,
these regression lines can be used to choose the number of requested iterations
to obtain reliable bounds on a given initial interval. With the parameters'
values that were chosen in the example, it appears that exact bounds on the
interval are obtained when
. Using
this value leads to a relative error less than
.
Therefore, events whose probability is more than
are almost exactly
described (this probability corresponds to
).
To prove the existence and unicity of an abscissa
such that
,
the main point is to observe that the difference between two successive
functions goes from negative values to positive values only once (Fig. 6,
left).
This situation can be derived from the fact that
is proportional to
, and therefore
we are intersecting
and
.
By the way (Fig. 6, right), we obtain a better conditionned
numerical equation. More precisely,
For increasing values of
,
becomes
indistinguishable from
, the
normal law with mean
and variance
,
while
converges towards
. But, for
sufficiently large
,
is indistinguishable from an exponential
law (large deviation theorem). When
is zero outside some finite domain,
we have the more precise result :
when
where
.
One obtains:
Therefore, intersecting
and
is equivalent to intersect a fixed (exponential) curve decreasing to
and a moving to right (bell) curve increasing from
, proving the existence
and unicity of
and the relation
.
Combining these relations, we obtain that, for a fixed
, the sequence
is increasing. Its limit is the requested
.
The core of the preceding proof being decreasing versus increasing (and not
exponential versus normal), the result still holds for small values of
(without requiring a formal proof, since a simple examination of the curves
is sufficient).
The computation from convolution of functions
has a cost, that needs to be evaluated carefully. For M/D/1 queues, the
are piecewise polynomial functions (
parts of degree
).
For the first iterations, it is efficient to use fractional numbers, while for
the next ones, it is necessary to use floating point numbers. Then it is necessary
to use a sufficient precision in order to avoid instability problems due to
inversion of Laplace transform [6].
We used up to 100 decimal digits (which let us get an accuracy of only 5 useful digits for the final result). Programming carefully and using recent computers allow to compute convolutions of piecewise functions up to 100 pieces, each of degree 100, but not more.